function ajax(url){
        var request = window.XMLHttpRequest ? new XMLHttpRequest() : new ActiveXObject("MSXML2.XMLHTTP.3.0");
		request.open("GET", url, true);
        request.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); 
		request.onreadystatechange = function(){
				if (request.readyState == 4 && request.status == 200) {
                        if (request.responseText){
                                ContactThankYou();
	                    }
                }
        }
        request.send(null);
}